Electrolysis Mass Calculator: Calculate Mass Deposited From Voltage


Electrolysis Mass Calculator

Calculate the mass of a substance deposited at the cathode using voltage, time, and other properties.



The potential difference applied across the electrodes, in Volts.


The total duration of the electrolysis process.



The total electrical resistance of the electrolyte and circuit, in Ohms.


The metal being deposited at the cathode. Molar mass and ion charge are handled automatically.

Mass Deposited

0.00 g

Current (I)

0.00 A

Total Charge (Q)

0.00 C

Moles Deposited (n)

0.00 mol

The mass is calculated based on Faraday’s Laws of Electrolysis, incorporating Ohm’s Law.

Mass Deposited Over Time

Visual representation of how mass accumulates at the cathode over the specified duration.

Deposition Timeline


Time Interval Mass Deposited (g)
A breakdown of the mass deposited at different intervals during the electrolysis process.

What is Electrolytic Deposition?

Electrolytic deposition is a process where a substance is deposited onto an electrode by passing an electric current through a solution containing its ions. This technique, central to electroplating and metal refining, is governed by Faraday’s laws of electrolysis. The setup involves two electrodes—an anode (positive) and a cathode (negative)—immersed in an electrolyte solution. When voltage is applied, positive ions (cations) in the solution migrate to the cathode, gain electrons (a process called reduction), and deposit as a neutral metal layer. The primary task of this page is to help you calculate the mass of anode deposited at cathode using voltage, though more accurately, it calculates the mass of material from the electrolyte deposited at the cathode. The anode itself is consumed in the process, releasing ions into the solution.

This calculator is essential for engineers, chemists, and hobbyists who need to predict the outcome of an electroplating or refining process without performing the experiment first. It helps in understanding how changing parameters like voltage or time affects the amount of material deposited.

The Formula to Calculate Mass Deposited via Electrolysis

To accurately calculate the mass deposited, especially when starting from voltage, we must combine two fundamental principles: Ohm’s Law and Faraday’s First Law of Electrolysis. The relationship isn’t direct; it requires several steps.

  1. Find Current (I): Using Ohm’s Law, `I = V / R`, where V is voltage and R is resistance.
  2. Find Total Charge (Q): Charge is current multiplied by time, `Q = I * t`.
  3. Find Moles of Electrons (n_e): The total charge is divided by Faraday’s constant (F ≈ 96,485 C/mol), `n_e = Q / F`.
  4. Find Moles of Substance (n): The moles of deposited substance depends on the ion’s charge (valence, z), `n = n_e / z`.
  5. Find Mass (m): Finally, mass is moles multiplied by the substance’s molar mass (M), `m = n * M`.

Combining these steps gives the comprehensive formula used by this calculator:

m = (V * t * M) / (R * F * z)

Formula Variables

Variable Meaning Unit (Auto-inferred) Typical Range
m Mass of substance deposited grams (g) 0 – 1,000+
V Applied Voltage Volts (V) 0.1 – 50
t Time seconds (s) 1 – 86,400
M Molar Mass of substance g/mol 20 – 200
R Resistance of the system Ohms (Ω) 1 – 10,000
F Faraday’s Constant C/mol ~96,485
z Valence (ion charge) (unitless integer) 1, 2, 3…

Practical Examples

Example 1: Copper Plating a Key

Imagine you want to plate a key with copper. You set up a cell with a 3V power source, the electrolyte and circuit have a total resistance of 15 Ω, and you run the process for 30 minutes.

  • Inputs: V = 3 V, Time = 30 min (1800 s), R = 15 Ω, Substance = Copper (M=63.55 g/mol, z=2).
  • Calculation:
    1. Current (I) = 3 V / 15 Ω = 0.2 A
    2. Charge (Q) = 0.2 A * 1800 s = 360 C
    3. Mass (m) = (360 C * 63.55 g/mol) / (96485 C/mol * 2) ≈ 0.119 g
  • Result: Approximately 0.119 grams (or 119 mg) of copper will be deposited on the key.

Example 2: Silver Coating Jewelry

An artist wants to coat a piece of bronze jewelry with pure silver. They use a precise 1.2V source, measure the resistance at 50 Ω, and leave it for 2 hours.

  • Inputs: V = 1.2 V, Time = 2 hours (7200 s), R = 50 Ω, Substance = Silver (M=107.87 g/mol, z=1).
  • Calculation:
    1. Current (I) = 1.2 V / 50 Ω = 0.024 A
    2. Charge (Q) = 0.024 A * 7200 s = 172.8 C
    3. Mass (m) = (172.8 C * 107.87 g/mol) / (96485 C/mol * 1) ≈ 0.193 g
  • Result: Approximately 0.193 grams of silver will be plated onto the jewelry. For more on silver plating, see our Guide to Precious Metal Plating.

How to Use This Electrolysis Mass Calculator

Using this tool is straightforward. Follow these steps to calculate the mass of substance deposited:

  1. Enter Applied Voltage: Input the voltage of your power source in Volts (V).
  2. Set the Time: Enter the duration of the electrolysis and select the appropriate unit (Hours, Minutes, or Seconds).
  3. Enter Circuit Resistance: Provide the total resistance of your electrolytic cell in Ohms (Ω). This is a critical value; an estimate is better than nothing. Learn more at our Ohm’s Law Calculator.
  4. Select the Substance: Choose the metal you are depositing from the dropdown menu. The calculator automatically handles its Molar Mass and typical ion charge (valence).
  5. Review the Results: The calculator instantly updates the total mass deposited, as well as intermediate values like current and total charge. The chart and table below will also update to reflect your inputs.

Key Factors That Affect Mass Deposition

The amount of mass deposited is influenced by several factors. Understanding these can help you control and optimize your electroplating results.

  • Current Density: This is the current per unit area of the cathode. While our calculator uses total current (derived from voltage and resistance), higher current density generally increases the rate of deposition. However, if too high, it can lead to a poor quality, porous deposit.
  • Time: As shown by Faraday’s law, the mass deposited is directly proportional to the time the current flows. Doubling the time will double the mass, assuming other conditions are stable.
  • Temperature: Higher temperatures often increase the conductivity of the electrolyte (lowering resistance) and can affect ion mobility, thus altering the deposition rate and the quality of the deposited layer.
  • Electrolyte Concentration: A higher concentration of metal ions near the cathode can support a higher rate of deposition. Depleted concentration can slow the process.
  • pH of the Solution: The acidity or alkalinity of the electrolyte can influence the reaction, sometimes leading to competing reactions like the evolution of hydrogen gas at the cathode, which reduces the efficiency of metal deposition.
  • Presence of Additives: Special chemicals are often added to electrolytes to act as brighteners, levelers, or stress-reducers, which dramatically affect the appearance and physical properties of the deposited layer without necessarily changing the mass.

Frequently Asked Questions (FAQ)

1. Why do I need resistance to calculate mass from voltage?
Faraday’s laws directly relate mass to electric charge (current × time), not voltage. Ohm’s Law (V = IR) is the bridge that connects voltage to current. Without knowing the circuit’s resistance (R), you cannot determine how much current (I) will flow for a given voltage (V).
2. What is Faraday’s Constant (F)?
Faraday’s Constant represents the total electric charge carried by one mole of electrons. It’s approximately 96,485 coulombs per mole. It’s a fundamental constant in electrochemistry that links macroscopic charge flow to the microscopic world of atoms and electrons.
3. What does the valence (z) mean?
Valence, or ion charge, is the number of electrons an ion needs to gain (or lose) to become a neutral atom. For example, a copper ion in a copper(II) sulfate solution is Cu²⁺, so it needs to gain 2 electrons. Its valence (z) is 2. A silver ion (Ag⁺) needs only one, so z=1.
4. Is the mass deposited at the cathode always equal to the mass lost from the anode?
Ideally, yes, if the anode is made of the same material being deposited (a soluble anode). However, if an inert anode (like platinum or carbon) is used, the anode does not dissolve. Instead, another reaction (like oxygen evolution from water) occurs at the anode.
5. What happens if the voltage is too high?
Excessively high voltage can cause a very high current density, leading to a “burnt,” powdery, or non-adherent deposit. It can also cause other unwanted reactions to occur, primarily the electrolysis of water, which produces hydrogen gas at the cathode and reduces the efficiency of your metal deposition.
6. Can this calculator be used for any substance?
It can be used for any substance deposited via electrolysis as long as you know its Molar Mass (M) and the valence (z) of its ion in the solution. We’ve pre-filled common examples, but the principle is universal.
7. How accurate is this calculation?
The calculation is theoretically perfect. In practice, real-world results may vary due to factors like current efficiency (side reactions), temperature fluctuations, and inaccuracies in measuring resistance. It provides a very strong theoretical baseline.
8. Where can I find the resistance of my electrolyte?
This is the most difficult parameter to determine without measurement. It depends on the electrolyte’s composition, concentration, temperature, and the distance between the electrodes. It often requires an impedance meter or can be estimated from conductivity data for specific solutions.

For further exploration into related topics, check out these resources:

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