Enthalpy of Fusion (ΔH) Calculator
This calculator determines the enthalpy of fusion (ΔHfus) based on the thermodynamic principle that at the melting point (a phase transition), the change in Gibbs free energy (ΔG) is zero. The calculation uses the formula: ΔHfus = Tfus × ΔSfus.
The temperature at which the substance melts.
The change in entropy when the substance melts.
Calculation Results
This is the calculated Enthalpy of Fusion (ΔHfus).
Intermediate Values
— K
— kJ/mol·K
0 kJ/mol
What is Calculating Enthalpy of Fusion using Gibbs Free Energy?
Calculating the enthalpy of fusion (ΔHfus) using Gibbs free energy is a fundamental application of thermodynamics. The enthalpy of fusion, also known as the latent heat of fusion, is the amount of energy required to change one mole of a substance from a solid to a liquid at constant temperature and pressure. This energy is used to overcome the intermolecular forces holding the solid’s crystal lattice together.
The Gibbs free energy (G) equation, ΔG = ΔH – TΔS, connects enthalpy (H), temperature (T), and entropy (S). A key principle is that during a phase transition, like melting (fusion), the system is in equilibrium. At equilibrium, the change in Gibbs free energy is zero (ΔG = 0). This simplifies the equation to 0 = ΔHfus – TfusΔSfus, which we can rearrange to find the enthalpy of fusion: ΔHfus = Tfus × ΔSfus. This calculator uses this exact relationship.
The Formula for Calculating Delta H using Fusion Gibbs
The calculation is based on the Gibbs free energy equation at the point of phase equilibrium (melting):
ΔHfus = Tfus × ΔSfus
Where the variables represent:
| Variable | Meaning | Unit (Auto-Inferred) | Typical Range |
|---|---|---|---|
| ΔHfus | Enthalpy of Fusion | kJ/mol | 0.5 – 50 kJ/mol |
| Tfus | Melting Point Temperature | Kelvin (K) | 50 – 3000 K |
| ΔSfus | Entropy of Fusion | J/mol·K | 5 – 100 J/mol·K |
For more details on thermodynamic calculations, our Thermodynamics Calculator provides a broader overview.
Practical Examples
Example 1: Melting Ice (Water)
Let’s calculate the enthalpy of fusion for water, which is a common real-world scenario.
- Inputs:
- Melting Point (Tfus): 0 °C
- Entropy of Fusion (ΔSfus): 22.0 J/mol·K
- Calculation Steps:
- Convert Temperature to Kelvin: Tfus = 0 °C + 273.15 = 273.15 K
- Calculate ΔHfus: ΔHfus = 273.15 K × 22.0 J/mol·K = 6009.3 J/mol
- Result:
- ΔHfus ≈ 6.01 kJ/mol. This is a well-established value for the enthalpy of fusion of water.
Example 2: Melting Benzene
Let’s consider an organic solvent, benzene.
- Inputs:
- Melting Point (Tfus): 5.5 °C
- Entropy of Fusion (ΔSfus): 35.3 J/mol·K
- Calculation Steps:
- Convert Temperature to Kelvin: Tfus = 5.5 °C + 273.15 = 278.65 K
- Calculate ΔHfus: ΔHfus = 278.65 K × 35.3 J/mol·K = 9835.3 J/mol
- Result:
- ΔHfus ≈ 9.84 kJ/mol. This shows that more energy is required to melt a mole of benzene compared to a mole of water. To understand the properties of gases, check out our Ideal Gas Law Calculator.
How to Use This Enthalpy of Fusion Calculator
- Enter Melting Point: Input the melting temperature of your substance into the “Melting Point Temperature” field.
- Select Temperature Unit: Use the dropdown to select the correct unit for your temperature value (Kelvin, Celsius, or Fahrenheit). The calculator will automatically convert it to Kelvin for the formula.
- Enter Entropy of Fusion: Input the entropy change of fusion for your substance. Explore more about entropy with our Entropy Calculator.
- Select Entropy Unit: Choose whether your entropy value is in J/mol·K or kJ/mol·K. The calculator will standardize it to kJ/mol·K.
- Interpret the Results: The main result, ΔHfus, is displayed prominently in kJ/mol. You can also view the intermediate values (temperature in Kelvin and entropy in kJ/mol·K) that were used in the calculation. The chart visualizes how Gibbs free energy changes around the melting point, crossing zero exactly at Tfus.
Key Factors That Affect Enthalpy of Fusion
Several molecular and physical factors influence the enthalpy of fusion:
- Intermolecular Forces: Stronger forces (like hydrogen bonds in water) require more energy to break, leading to a higher ΔHfus.
- Molecular Size and Shape: Larger, more complex molecules often have higher enthalpies of fusion due to increased van der Waals interactions. Symmetrical molecules may pack more efficiently into a crystal, requiring more energy to disrupt.
- Crystal Lattice Structure: The arrangement of molecules in the solid state affects the energy required to break it apart. A more stable, tightly packed crystal generally has a higher ΔHfus.
- Pressure: While the effect is often small for solid-liquid transitions, pressure can slightly alter the melting point and thus the enthalpy of fusion. This is explored further in phase diagrams, which you can generate with a Phase Diagram Generator.
- Purity of the Substance: Impurities disrupt the crystal lattice, typically lowering the melting point and affecting the overall energy required for fusion.
- Entropy Change (ΔSfus): This reflects the increase in disorder from solid to liquid. Substances that become significantly more disordered upon melting will have a larger ΔSfus, directly increasing ΔHfus.
Frequently Asked Questions (FAQ)
1. Why is Gibbs Free Energy (ΔG) zero at the melting point?
At the melting point, the solid and liquid phases are in equilibrium. This means the rate of melting equals the rate of freezing. By definition, a system at equilibrium has a Gibbs free energy change of zero because it has no net tendency to proceed in either the forward or reverse direction.
2. What is the difference between enthalpy of fusion and heat of fusion?
The terms are often used interchangeably. “Enthalpy of fusion” is the more formal thermodynamic term, representing the change in enthalpy (ΔH) for the process. “Heat of fusion” refers to the same quantity of energy but is often expressed per gram instead of per mole.
3. Can I use this calculator for boiling (vaporization)?
Yes, the principle is the same. For boiling, you would use the boiling point temperature (Tvap) and the entropy of vaporization (ΔSvap) to calculate the enthalpy of vaporization (ΔHvap). Just be sure to input the correct corresponding values.
4. Why does the temperature need to be in Kelvin?
Thermodynamic calculations, especially those involving entropy (which has units of Joules per Kelvin), require an absolute temperature scale. Kelvin is the standard SI unit for temperature where 0 K represents absolute zero, ensuring formulas like the Gibbs free energy equation work correctly.
5. What does a negative enthalpy of fusion mean?
A positive ΔHfus represents melting (energy absorbed). A negative value of the same magnitude represents the reverse process: freezing (solidification), where energy is released.
6. What does the chart of Gibbs Free Energy vs. Temperature show?
The chart illustrates that for temperatures below the melting point (T < Tfus), ΔG is positive, meaning melting is not spontaneous. For temperatures above the melting point (T > Tfus), ΔG is negative, so melting is spontaneous. Exactly at the melting point (T = Tfus), the line crosses the axis, showing ΔG = 0, the point of equilibrium.
7. Is this related to a Gibbs Free Energy Calculator?
Yes, this calculator is a specific application of the Gibbs free energy concept. A general Gibbs Free Energy Calculator would solve for ΔG, ΔH, or ΔS given the other variables for any process, not just a phase change.
8. Where can I find values for entropy of fusion (ΔSfus)?
These values are determined experimentally and can be found in chemistry textbooks, scientific handbooks (like the CRC Handbook of Chemistry and Physics), and online chemical databases.